procedure heapsort(a, count) is
input: an unordered array a of length count
(Build the heap in array a so that largest value is at the root)
heapify(a, count)
(The following loop maintains the invariants that a[0:end] is a heap and every element
beyond end is greater than everything before it (so a[end:count] is in sorted order))
end ← count - 1
while end > 0 do
(a[0] is the root and largest value. The swap moves it in front of the sorted elements.)
swap(a[end], a[0])
(the heap size is reduced by one)
end ← end - 1
(the swap ruined the heap property, so restore it)
siftDown(a, 0, end)
(Put elements of 'a' in heap order, in-place)
procedure heapify(a, count) is
(start is assigned the index in 'a' of the last parent node)
(the last element in a 0-based array is at index count-1; find the parent of that element)
start ← iParent(count-1)
while start ≥ 0 do
(sift down the node at index 'start' to the proper place such that all nodes below
the start index are in heap order)
siftDown(a, start, count - 1)
(go to the next parent node)
start ← start - 1
(after sifting down the root all nodes/elements are in heap order)
(Repair the heap whose root element is at index 'start', assuming the heaps rooted at its children are valid)
procedure siftDown(a, start, end) is
root ← start
while iLeftChild(root) ≤ end do (While the root has at least one child)
child ← iLeftChild(root) (Left child of root)
swap ← root (Keeps track of child to swap with)
if a[swap] < a[child]
swap ← child
(If there is a right child and that child is greater)
if child+1 ≤ end and a[swap] < a[child+1]
swap ← child + 1
if swap = root
(The root holds the largest element. Since we assume the heaps rooted at the
children are valid, this means that we are done.)
return
else
swap(a[root], a[swap])
root ← swap (repeat to continue sifting down the child now)
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